getting user input and checking if it's valid
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8a80ac9f26
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@ -4,6 +4,7 @@ import java.util.ArrayList;
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import java.util.HashMap;
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import java.util.List;
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import java.util.Map;
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import java.util.Scanner;
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import fr.packageviewer.pack.SearchedPackage;
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@ -69,6 +70,7 @@ public class Main {
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}
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}
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// list all packages in reverse order
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for (int i = packets.size(); i-- > 0; ) {
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SearchedPackage searchedPacket = packets.get(i);
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System.out.printf("%s - %s/%s/%s %s%n\t%s%n",
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@ -79,5 +81,51 @@ public class Main {
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searchedPacket.getVersion()==null?"":searchedPacket.getVersion(),
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searchedPacket.getDescription());
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}
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System.out.printf("Pick a package to see in details (0-%s) : %n", packets.size()-1);
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Scanner input = new Scanner(System.in);
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// we create vars for the loop
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String packetNumberString;
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int packetNumber;
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boolean notValid;
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// we ask input and check if the user input is correct
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do {
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packetNumberString = input.nextLine();
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// reset notValid to false, we set it in true only if something is wrong
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notValid = false;
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if(isNumeric(packetNumberString)) {
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packetNumber = Integer.parseInt(packetNumberString);
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if(packetNumber < 0 || packetNumber >= packets.size()) {
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// this number is too big or too small
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System.out.println("Enter a valid number");
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notValid = true;
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}
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} else {
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// this is not a number
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System.out.println("Enter a valid number");
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notValid = true;
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}
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} while(notValid);
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input.close();
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}
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/**
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* Check if the String given is a number
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* @param i the String given
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* @return true if the String is a number
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* @author Capelier-Marla
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*/
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private static boolean isNumeric(String i) {
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try {
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Integer.parseInt(i);
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return true;
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} catch (Exception e) {
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return false;
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}
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}
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}
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